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  2. Jul 09, 2016
    • Sander, Oliver's avatar
      Use a true second-order function as the base of the second-order vector field · d1cbcb59
      Sander, Oliver authored
      It seemed strange to me to demonstrate a second-order tangent field on a
      first-order base function.  People may think that this is a necessary restriction.
      
      Also, this patch includes a bugfix:  The basis of the tangent space was hard-wired
      to (0,1,0) and (0,0,1).  But this only works if we are at the tangent space at (1,0,0).
      d1cbcb59
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